document.write( "Question 1021093: So if a rhombus has a diagonal of 14 and 2x+7y-3, how would you find the perimeter? With the diagonal of 2x+7y-3, one side of the diagonal is 3x and the other side is 5y-1.
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Algebra.Com's Answer #636860 by ikleyn(52915)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "So if a rhombus has a diagonal of 14 and 2x+7y-3, how would you find the perimeter?
\n" ); document.write( "With the diagonal of 2x+7y-3, one side of the diagonal is 3x and the other side is 5y-1.
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\n" ); document.write( "\n" ); document.write( "What should I do: write my (the correct) solution, or comment yours (incorrect)?\r
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\n" ); document.write( "Comment from student: Please write the correct solution. Thank you.
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\n" ); document.write( "\n" ); document.write( "OK.\r
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document.write( "The diagonals divide the rhombus in four congruent right-angled triangles.\r\n" );
document.write( "They have the legs of half the diagonals, i.e. \"7%2F2\" units long and \"%282x%2B7y-3%29%2F2\" units long.\r\n" );
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document.write( "According to the Pythagorean theorem, the side of the rhombus has the length\r\n" );
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document.write( "\"sqrt%28%287%2F2%29%5E2+%2B+%28%282x%2B7y-3%29%2F2%29%5E2%29\".\r\n" );
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document.write( "The perimeter of the rhombus is four times this length, i.e.\r\n" );
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document.write( "\"4%2Asqrt%28%287%2F2%29%5E2+%2B+%28%282x%2B7y-3%29%2F2%29%5E2%29\".\r\n" );
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\n" ); document.write( "Comment from student #2: I'm sorry but I don't understand still. On my worksheet it says that
\n" ); document.write( "the diagonal that is 2x+7y-3, is split into two and one side of it is 3x and the other is 5y-1.
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\n" ); document.write( "\n" ); document.write( "OK.\r
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document.write( "I see that we do not understand each other.\r\n" );
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document.write( "Then please \r\n" );
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document.write( "1. Disregard and ignore what I responded to you.\r\n" );
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document.write( "2. Resubmit your assignment, word-by-word, to the forum and somebody will help you.\r\n" );
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document.write( "   Do not add any additional word from yourself to the assignment formulation.\r\n" );
document.write( "   Only the assignment formulation as is.\r\n" );
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