document.write( "Question 1021091: Consider the line y=-7x+9\r
\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is perpendicular to this line and passes through the point (5,-2)\r
\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is parallel to this line and passes through the point (5,-2)
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Algebra.Com's Answer #636857 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
You can stay completely in slope-intercept form if you want to.
\n" ); document.write( "\"y=mx%2Bb\"
\n" ); document.write( "\"y-mx=b\"
\n" ); document.write( "\"b=y-mx\"
\n" ); document.write( "which you can reform as \"highlight_green%28y=mx%2B%28y%5Br%5D-mx%5Br%5D%29%29\" for whatever reference point with those coordinates you have.\r
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\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is perpendicular to this line and passes through the point (5,-2)
\n" ); document.write( "This needs m=\"1%2F7\", which is negative reciprocal of the slope in your given equation. That makes the line you want PERPENDICULAR.
\n" ); document.write( "\"highlight%28y=%281%2F7%29x%2B%28-2-%281%2F7%29%2A5%29%29\", which you just need to simplify.\r
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\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is parallel to this line and passes through the point (5,-2)
\n" ); document.write( "The slope here will be \"m=-7\"; do this one on your own.
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