document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87676>Question 87676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The right cone has a r = 4 in. and h = 3 in., find the total surface area?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63684 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "     r=4 in  h=3 in   total surface area of the cone = pi.r(r+l)<BR>\n" );
document.write( "                                                     = 22/7.4(4+3)<BR>\n" );
document.write( "                                                     = 22/7.4.7<BR>\n" );
document.write( "                                                     = 22.4.7/7<BR>\n" );
document.write( "                                                     =22.4 <BR>\n" );
document.write( "                                                     =88 sq.in </SPAN>\n" );
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