document.write( "Question 1021060: if the width of a rectangle is four feet less than the length and the perimeter is 152 feet, find the length of the rectangle.
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Algebra.Com's Answer #636831 by macston(5194) You can put this solution on YOUR website! L=length; W=width=L-4ft \n" ); document.write( ". \n" ); document.write( "P=2(L+W) \n" ); document.write( "152 feet=2(L+(L-4ft)) \n" ); document.write( "76ft=2L-4ft \n" ); document.write( "80ft=2L \n" ); document.write( "40ft=L \n" ); document.write( ". \n" ); document.write( "ANSWER: The length of the rectangle is 40 feet. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "W=L-4ft=40ft-4ft=36ft \n" ); document.write( "Width is 36 feet. \n" ); document.write( "P=2(L+W) \n" ); document.write( "152 feet=2(40ft+36ft) \n" ); document.write( "152 feet=2(76ft) \n" ); document.write( "152 feet=152 feet \n" ); document.write( ".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |