document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1020918>Question 1020918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question\r<BR>\n" );
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document.write( "If an isosceles triangle ABC in which AB=AC=6cm is inscribed in a circle of radius       9cm find the area of the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #636810 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=636810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem can not be solved<BR>\n" );
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document.write( "we are given AB=AC=6cm<BR>\n" );
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document.write( "The altitude of the isosceles triangle ABC is the perpendicular bisector of the base AC, let the point of intersection of the altitude and AC be D, then<BR>\n" );
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document.write( "ADC is a right triangle and we know that angle ADC is 90 degrees<BR>\n" );
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document.write( "The side opposite 90 degrees in a right triangle is the longest side - the hypotenuse<BR>\n" );
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document.write( "side AD = radius of circle + x where x > 0, therefore we have<BR>\n" );
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document.write( "AD = 9cm + x > AC = 6cm, a contradiction<BR>\n" );
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