document.write( "Question 87741: Help! I'm having difficulties figuring this problem out! Thank you in advance for your help! \r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 1 cm more than 2 times its width. If the area of the rectangle is 76 cm^2, find the dimensions of the rectangle to the nearest thousandth.
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Algebra.Com's Answer #63676 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( " Let the width of the rectangle be=xcms
\n" ); document.write( " the length of the rectangle(l) =2x+1 cms
\n" ); document.write( " area of the rectangle=l.b=76 cms^2
\n" ); document.write( " l.b=76 i.e (2x+1).x=76 2x^2+x-76=0
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\n" ); document.write( " since the factors cannot be found we factorise the eq'nusing the formula
\n" ); document.write( " we get two values for x x=5.9 & x=-6.4
\n" ); document.write( " we consider the +ve value for x width = 5.9cms = 0.059mts
\n" ); document.write( " length = 2(5.9)+1=11.8+1 12.8 = 0.128mts
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