document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1020948>Question 1020948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Often sales of a new product grow rapidly at first and then level off with time. This is the case with sales represented by the function S(t)=600-200t^-2, where t represents time in years. Find the rate of change of sales for the following number of years.<BR>\n" );
document.write( "1.	2 years<BR>\n" );
document.write( "2.	7 years\r<BR>\n" );
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document.write( "I thought I just replace t in the equation with the respective years but apparently that’s wrong?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #636750 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=636750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "S(t) = 600 - 200t^-2<BR>\n" );
document.write( "2 years<BR>\n" );
document.write( "S(t) = 600 - 200 x 2^-2<BR>\n" );
document.write( "S(t) = 550<BR>\n" );
document.write( "7 years<BR>\n" );
document.write( "S(t) = 600 - 200 t^-2<BR>\n" );
document.write( "S(t) = 600 - 200 x 7^-2<BR>\n" );
document.write( "S(t) = 595.9 (1 decimal place)<BR>\n" );
document.write( "2^-2 = 1/4<BR>\n" );
document.write( "7^-2 = 1/49<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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