document.write( "Question 1020915: Simplify\r
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document.write( "Log base 3(17/25) + log base 3(600/119) - log base 3(8/7) \n" );
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Algebra.Com's Answer #636741 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Log base 3(17/25) + log base 3(600/119) \n" ); document.write( "Using logb(mn) = logb(m) + logb(n) \n" ); document.write( "log base 3 ( 17/25 x 600/119) \n" ); document.write( "Cancel out 17:119 to get 1:7 \n" ); document.write( "Cancel out 25:600 to get 1:24 \n" ); document.write( "Log base 3 (1/1 x 24/7) \n" ); document.write( "Log base 3 (24/7) \n" ); document.write( "............. \n" ); document.write( "Log base 3 (24/7) - log base 3 (8/7) \n" ); document.write( "Using logb(m/n) = logb(m) – logb(n) \n" ); document.write( "log base 3 (24/7 divided by 8/7) \n" ); document.write( "Log base 3 (24/7 x 7/8) \n" ); document.write( "Cancel out 7:7 to get 1:1 \n" ); document.write( "Cancel out 24:8 to get 3:1 \n" ); document.write( "Log base 3 (3) \n" ); document.write( "Using log base a (a) = 1 \n" ); document.write( "Log base 3 (3) = 1 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |