document.write( "Question 1020921: A circle whose centre lies on the line y=3x-1, touches both axes. Find the equation of the circle, which I found to be 4x^2+4y^2-4x-4y+1=0 and find the points where the circle intersects the line 2y+x=1. \n" ); document.write( "

Algebra.Com's Answer #636724 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "A circle whose centre lies on the line y=3x-1, touches both axes. Find the equation of the circle,
\n" ); document.write( "which I found to be 4x^2+4y^2-4x-4y+1=0 and find the points where the circle intersects the line 2y+x=1.
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document.write( "1. I confirm that you correctly determined the equation of the circle.\r\n" );
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document.write( "2. To find intersection points, express x = 1 - 2y from the equation of the straight line, and substitute it into the circle equation.\r\n" );
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document.write( "   You will get a single quadratic equation for x.\r\n" );
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document.write( "   Its solution will give you the x-coordinates of the intersection points.\r\n" );
document.write( "   When you get x-coordinates, you can restore y-coordinates using the same equation 2y+x=1 of the straight line.\r\n" );
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