document.write( "Question 1020892: A boat takes 3 hours to go 9 miles upstream. It can go 18 miles downstream in the same time. Find the rate of the current and the rate of the boat in still water. (Hint: Because the current pushes the boat when it is going downstream, the rate of the boat downstream is the sum of the rate of the boat and the rate of the current. The current slows down the boat when it is going upstream, so the rate of the boat upstream is the difference of the rate of the boat and the rate of the current.) \n" ); document.write( "

Algebra.Com's Answer #636712 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
Implied variable assignings,\r
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document.write( "                 rate             time            distance\r\n" );
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document.write( "UP              r-c                3                 9\r\n" );
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document.write( "DOWN            r+c                3                18\r\n" );
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\n" ); document.write( "\n" ); document.write( "Form the system according to RT=D,
\n" ); document.write( " $\"system%28%28r-c%29%2A3=9%2C%28r%2Bc%29%2A3=18%29\"$
\n" ); document.write( "and solve the system. \n" ); document.write( "

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