document.write( "Question 1020900: I need the answers to these questions:\r
\n" ); document.write( "\n" ); document.write( "|(2x+(1/3))x +0.3|=3.5\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "|(-2x+(1/3))x+0.3|=3.5
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Algebra.Com's Answer #636708 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
They are somewhat alike, and if you understand how to handle either, you can handle the other.\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28%282x%2B%281%2F3%29%29x%2B0.3%29=3.5\"\r
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\n" ); document.write( "\n" ); document.write( "Distribute.
\n" ); document.write( "\"abs%282x%5E2%2Bx%2F3%2B0.3%29=3.5\"
\n" ); document.write( "Maybe easier if clear the fractions denominators...
\n" ); document.write( "\"3%2Aabs%282x%5E2%2Bx%2F3%2B0.3%29=3%2A%283.5%29\"
\n" ); document.write( "\"abs%286x%5E2%2Bx%2B0.9%29=10.5\", not perfectly, but good enough to continue comfortably.\r
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\n" ); document.write( "\n" ); document.write( "Either the input to the absolute value is non-negative, or it is negative. Solve for each of these two cases.\r
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\n" ); document.write( "\n" ); document.write( "NON-NEGATIVE
\n" ); document.write( "\"6x%5E2%2Bx%2B0.9=10.5\"
\n" ); document.write( "\"6x%5E2%2Bx%2B0.9-10.5=0\"
\n" ); document.write( "\"6x%5E2%2Bx-9.6=0\"
\n" ); document.write( "Discrim is \"1%2B4%2A6%2A9.6=231.4\"\r
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\n" ); document.write( "\n" ); document.write( "NEGATIVE
\n" ); document.write( "\"-6x%5E2-x-0.9=10.5\"
\n" ); document.write( "\"6x%5E2%2Bx%2B0.9=-10.5\"
\n" ); document.write( "\"6x%5E2%2Bx%2B0.9%2B10.5=0\"
\n" ); document.write( "\"6x%5E2%2Bx%2B11.4=0\"
\n" ); document.write( "Discrim is \"1-4%2A6%2A11.4=negativeValueDiscriminant\"
\n" ); document.write( "These will not be real numbers.\r
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\n" ); document.write( "\n" ); document.write( "Continue for the non-negative inputs to the absolute value.
\n" ); document.write( "\"highlight%28x=%28-1%2B-+sqrt%28231.4%29%29%2F12%29\"\r
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\n" ); document.write( "\n" ); document.write( "You may want to check both values in case one of them does not work in the original equation.
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