document.write( "Question 1020900: I need the answers to these questions:\r
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document.write( "|(2x+(1/3))x +0.3|=3.5\r
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document.write( "and\r
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document.write( "|(-2x+(1/3))x+0.3|=3.5 \n" );
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Algebra.Com's Answer #636708 by josgarithmetic(39625)![]() ![]() ![]() You can put this solution on YOUR website! They are somewhat alike, and if you understand how to handle either, you can handle the other.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distribute. \n" ); document.write( " \n" ); document.write( "Maybe easier if clear the fractions denominators... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Either the input to the absolute value is non-negative, or it is negative. Solve for each of these two cases.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "NON-NEGATIVE \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Discrim is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "NEGATIVE \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Discrim is \n" ); document.write( "These will not be real numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Continue for the non-negative inputs to the absolute value. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You may want to check both values in case one of them does not work in the original equation. \n" ); document.write( " |