document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1020758>Question 1020758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the gradient of a line which is perpendicular to line y = -2x + 1\r<BR>\n" );
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document.write( "Explanation please. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #636602 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=636602\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "y = -2x + 1<BR>\n" );
document.write( "Gradient = -2<BR>\n" );
document.write( "Lines that are perpendicular to<BR>\n" );
document.write( "one another have gradients that<BR>\n" );
document.write( "multiply together to give -1<BR>\n" );
document.write( "m1 x m2 = -1<BR>\n" );
document.write( "-2 x m2 = -1<BR>\n" );
document.write( "m2 = -1/-2<BR>\n" );
document.write( "m2 = 1/2<BR>\n" );
document.write( "The gradient of the line<BR>\n" );
document.write( "perpendicular to y = -2x + 1<BR>\n" );
document.write( "is 1/2<BR>\n" );
document.write( "hope this helps :-) </SPAN>\n" );
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