document.write( "Question 1020705: How to solve this limit?\r
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Algebra.Com's Answer #636569 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming the original limit is
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\n" ); document.write( "\n" ); document.write( "If so, then here are the steps\r
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Step NumberExpression
1. \"lim%28x-%3E0%2C+++%28cos%282x%29+-+cos%28x%29%29%2F%28x%29%29\"
2. \"lim%28x-%3E0%2C+++%282cos%5E2%28x%29+-+1+-+cos%28x%29%29%2F%28x%29%29\"
3. \"lim%28x-%3E0%2C+++%282cos%5E2%28x%29+-+cos%28x%29+-+1%29%2F%28x%29%29\"
4. \"lim%28x-%3E0%2C+++%28%282cos%28x%29%2B1%29%28cos%28x%29-1%29%29%2F%28x%29%29\"
5. \"lim%28x-%3E0%2C+++%282cos%28x%29%2B1%29%2A%28%28%28cos%28x%29-1%29%29%2F%28x%29%29%29\"
6.
7. \"lim%28x-%3E0%2C+++%282cos%28x%29%2B1%29%29%2A0\"
8. \"%282%2Acos%280%29%2B1%29%2A0\"
9. \"%282%2A1%2B1%29%2A0\"
10. \"%282%2B1%29%2A0\"
11. \"3%2A0\"
12. \"0\"
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\n" ); document.write( "\n" ); document.write( "In step 2, I used the trig identity \"cos%282x%29+=+2cos%5E2%28x%29-1\" (see page 2 under \"Double Angle Formulas\")\r
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\n" ); document.write( "\n" ); document.write( "In step 6, I broke up the limit using the limit law \r
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\n" ); document.write( "\n" ); document.write( "In step 7, I used the special trig limit \"lim%28x-%3E0%2C+++%28%28cos%28x%29-1%29%2Fx%29%29+=+0\" (scroll down to bottom half of the page)\r
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\n" ); document.write( "\n" ); document.write( "From step 8 and beyond, I used the substitution rule and then evaluated/simplified to get the final answer of 0\r
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\n" ); document.write( "\n" ); document.write( "So in the end,
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\n" ); document.write( "\n" ); document.write( "Final Answer: 0
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