document.write( "Question 1020566: A motorboat heads upstream a distance of 24 miles on a river whose current is running at 3 miles per hour. The motorboat then returns to the original place heading downstream. The total trip up and back takes 6 hours. What was the speed of the motorboat assuming it maintained a constant speed? \n" ); document.write( "
Algebra.Com's Answer #636452 by ankor@dixie-net.com(22740)\"\" \"About 
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A motorboat heads upstream a distance of 24 miles on a river whose current is running at 3 miles per hour.
\n" ); document.write( " The motorboat then returns to the original place heading downstream.
\n" ); document.write( " The total trip up and back takes 6 hours.
\n" ); document.write( " What was the speed of the motorboat assuming it maintained a constant speed?
\n" ); document.write( ":
\n" ); document.write( "let s = the speed of the boat in still water
\n" ); document.write( "then
\n" ); document.write( "(s-3) = effective speed upstream
\n" ); document.write( "and
\n" ); document.write( "(s+3) = effective speed downstream
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Time up + time down = 6 hrs
\n" ); document.write( "\"24%2F%28s-3%29\" + \"24%2F%28s%2B3%29\" = 6
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by (s-3)(s+3), cancel the denominators and you have
\n" ); document.write( "24(s+3) + 24(s-3) = 6(s-3)(s+3)
\n" ); document.write( "24s + 72 + 24s - 72 = 6(s^2 - 9)
\n" ); document.write( "48s = 6s^2 - 54
\n" ); document.write( "A quadratic equation
\n" ); document.write( "0 = 6s^2 - 48s - 54
\n" ); document.write( "Simplify, divide by 6
\n" ); document.write( "s^2 - 8s - 9 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(s - 9) (s + 1) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "s = 9 mph the speed of the boat in still water
\n" ); document.write( ":
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\n" ); document.write( ":
\n" ); document.write( "Check this, find the time each way
\n" ); document.write( "24/6 = 4 hrs upstream
\n" ); document.write( "24/12 = 2 hrs down
\n" ); document.write( "-------------------
\n" ); document.write( "total: 6 hrs
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