document.write( "Question 12517: the modern grocery has cashews that sell for $3.50 a pound and peanuts that sell for $2.00 a pound. how much of each must Alberts, the grocer, mix to get 60 pounds of mixture that he can sell for $3.00 per pound. Express the problem as a system of linear equations and solve using the method of your choice to find the solution. \n" ); document.write( "
Algebra.Com's Answer #6364 by Earlsdon(6294)\"\" \"About 
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Let C = the required number of lbs of cashews.
\n" ); document.write( "Let P = the required number of lbs of peanuts.\r
\n" ); document.write( "\n" ); document.write( "1) Express as a system of linear equations:\r
\n" ); document.write( "\n" ); document.write( "a) \"%283.50%29C+%2B+%282.00%29P+=+3.00%2860%29\" and
\n" ); document.write( "b) \"C+%2B+P+=+60\"\r
\n" ); document.write( "\n" ); document.write( "2) Solve: Rewrite equation b) as: \"P+=+60+-+C\" and substitute into equation a) and solve for P.\r
\n" ); document.write( "\n" ); document.write( "a) \"%283.50%29C+%2B+%282.00%29%2860+-+C%29+=+3.00%2860%29\" Simplify and solve for C.\r
\n" ); document.write( "\n" ); document.write( "\"3.5C+%2B+120+-+2C+=++180\"
\n" ); document.write( "\"1.5C+%2B+120+=+180\"
\n" ); document.write( "\"1.5C+=+60\"
\n" ); document.write( "\"C+=+40\" 40 lbs of cashews are required.\r
\n" ); document.write( "\n" ); document.write( "\"P+=+60+-+C\"
\n" ); document.write( "\"P+=+60+-+40\"
\n" ); document.write( "\"P+=+20\" 20 lbs of peanuts are are required.
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