document.write( "Question 1020439: Im really stuck!
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document.write( "ABC is an isosceles triangle. The coordinates of A and B are (5,6) and (0,-4) respectively. Given that the gradient of BC is 3/4 and D is the midpoint of BC find:\r
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document.write( "Equation of AD\r
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document.write( "and\r
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document.write( "Coordinate of D,\r
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document.write( "how do i find equation of AD only with 2 points? \n" );
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Algebra.Com's Answer #636336 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! Given D is the midpoint of B and C, then points on AD are equidistant from points B and C. AD is the perpendicular bisector. \n" ); document.write( ": \n" ); document.write( "Given gradient of BC is 3/4, the slope of line BC is 3/4, then \n" ); document.write( ": \n" ); document.write( "y = 3x/4 + b \n" ); document.write( ": \n" ); document.write( ": use point B, (0,-4) to find b \n" ); document.write( ": \n" ); document.write( "-4 = 3(0)/4 + b \n" ); document.write( ": \n" ); document.write( "b = -4 \n" ); document.write( ": \n" ); document.write( "The equation of line BC is \n" ); document.write( ": \n" ); document.write( "y = 3x/4 -4 \n" ); document.write( ": \n" ); document.write( "since AD is perpendicular to BC, the slope of AD is -4x/3 \n" ); document.write( ": \n" ); document.write( "use point A, (5,6) to find b \n" ); document.write( ": \n" ); document.write( "6 = -4(5)/3 + b \n" ); document.write( ": \n" ); document.write( "18 = -20 + 3b \n" ); document.write( ": \n" ); document.write( "3b = 38 \n" ); document.write( ": \n" ); document.write( "b = 38/3 \n" ); document.write( ": \n" ); document.write( "************************** \n" ); document.write( "Equation of AD is \n" ); document.write( ": \n" ); document.write( "y = -4x/3 + 38/3 \n" ); document.write( "************************** \n" ); document.write( ": \n" ); document.write( "Now set the two lines = to each other to find point D \n" ); document.write( ": \n" ); document.write( "3x/4 -4 = -4x/3 + 38/3 \n" ); document.write( ": \n" ); document.write( "9x -48 = -16x + 152 \n" ); document.write( ": \n" ); document.write( "25x = 200 \n" ); document.write( ": \n" ); document.write( "x = 8 \n" ); document.write( ": \n" ); document.write( "substitute for x in equation for BC \n" ); document.write( ": \n" ); document.write( "y = 3(8)/4 -4 \n" ); document.write( ": \n" ); document.write( "y = 2 \n" ); document.write( ": \n" ); document.write( "************************ \n" ); document.write( "point D is (8,2) \n" ); document.write( "*********************** \n" ); document.write( " |