document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1020409>Question 1020409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cylindrical can of radius 7 cm and height 8 cm is open at one end. What is the external surface area of the can correct to 2 decimal places? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #636314 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=636314\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hi there,<BR>\n" );
document.write( "Surface area = Pi x radius^2 + (Pi x diameter) x height.<BR>\n" );
document.write( "Surface area = Pi x 7^2 + (Pi x 14)x 8<BR>\n" );
document.write( "Surface area = 505.80 cm^2<BR>\n" );
document.write( "The surface area of the can is found by<BR>\n" );
document.write( "using the circumference of the can as <BR>\n" );
document.write( "one side of the rectangle that is the <BR>\n" );
document.write( "opened can. The other side is the height.<BR>\n" );
document.write( "You then use Pi x r^2 for the end of the can.<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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