document.write( "Question 1020365: A woman earns $2,100 in interest from two accounts in a year. If she has three times as much invested at 8% as she does at 6%, how much does she have in each account?\r
\n" ); document.write( "\n" ); document.write( "I know I have to make a systems of equations, and I have 2,100=3a+b but im not sure if thats right or what the other one would be
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Algebra.Com's Answer #636304 by MathTherapy(10555)\"\" \"About 
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\n" ); document.write( "A woman earns $2,100 in interest from two accounts in a year. If she has three times as much invested at 8% as she does at 6%, how much does she have in each account?\r
\n" ); document.write( "\n" ); document.write( "I know I have to make a systems of equations, and I have 2,100=3a+b but im not sure if thats right or what the other one would be
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Let amounts invested in 8% and 6% funds, be E, and S, respectively
\n" ); document.write( "Then equation for amounts invested is: E = 3S
\n" ); document.write( "Interest equation: .08E + .06S = 2,100 \n" ); document.write( "
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