document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1020377>Question 1020377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation for the line that contains the point (-1 2) and is perpendicular to the line 3x+5y=7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #636262 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=636262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The line would have the form 5x - 3y = c, for some particular constant c.  To find this value, substitute the coordinates of the point into this equation:\r<BR>\n" );
document.write( "\n" );
document.write( "5*(-1) - 3*2 = -5 - 6 = -11 = c.\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore, the line that contains the point (-1 2) and is perpendicular to the line 3x+5y=7 is 5x - 3y = -11. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );