document.write( "Question 1020360: Hi, I'm confused on how to approach this problem. \r
\n" ); document.write( "\n" ); document.write( "It says to solve on the interval 0 <= theta < 2pi. \r
\n" ); document.write( "\n" ); document.write( "Question:\r
\n" ); document.write( "\n" ); document.write( "cotangent(2theta/3) = -square root 3 \r
\n" ); document.write( "\n" ); document.write( "Thanks!
\n" ); document.write( "

Algebra.Com's Answer #636260 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Where is the cotangent negative?
\n" ); document.write( "1st quadrant:
\n" ); document.write( "+/+ = +
\n" ); document.write( "2nd qudrant:
\n" ); document.write( "-/+ = -
\n" ); document.write( "3rd quadrant:
\n" ); document.write( "-/- = +
\n" ); document.write( "4th qudrant:
\n" ); document.write( "+/- = -
\n" ); document.write( "---------------
\n" ); document.write( "So it can be in the
\n" ); document.write( "2nd or 4th qudrant
\n" ); document.write( "-----------------
\n" ); document.write( "\"+cot%28+2%2Atheta+%2F+3+%29+=+-+sqrt%283%29+\"
\n" ); document.write( "I can say:
\n" ); document.write( "\"+2%2Atheta%2F3+=+arccot%28+-sqrt%283%29+%29+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "I know that \"+cot%28+pi%2F6+%29+=+sqrt%283%29+\" so
\n" ); document.write( "\"+arccot%28++-sqrt%28+3+%29%29+=+pi+-+pi%2F6+\"
\n" ); document.write( "\"+arccot%28+-sqrt%283%29+%29+=+2%2Api+-+pi%2F6+\"
\n" ); document.write( "-------------------------------
\n" ); document.write( "\"+2%2Atheta%2F3+=+5%2Api%2F6+\"
\n" ); document.write( "\"+theta+=+%283%2F2%29%2A%28+5%2Api%2F6+%29+\"
\n" ); document.write( "\"+theta+=+15%2Api%2F12+\"
\n" ); document.write( "and
\n" ); document.write( "\"+2%2Atheta%2F3+=+11%2Api%2F6+\"
\n" ); document.write( "\"+theta+=+%283%2F2%29%2A%28+11%2Api%2F6+%29+\"
\n" ); document.write( "\"+theta+=+33%2Api%2F12+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "Hope I got it!
\n" ); document.write( "
\n" );