document.write( "Question 1020360: Hi, I'm confused on how to approach this problem. \r
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document.write( "It says to solve on the interval 0 <= theta < 2pi. \r
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document.write( "Question:\r
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document.write( "cotangent(2theta/3) = -square root 3 \r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #636260 by josmiceli(19441) You can put this solution on YOUR website! Where is the cotangent negative? \n" ); document.write( "1st quadrant: \n" ); document.write( "+/+ = + \n" ); document.write( "2nd qudrant: \n" ); document.write( "-/+ = - \n" ); document.write( "3rd quadrant: \n" ); document.write( "-/- = + \n" ); document.write( "4th qudrant: \n" ); document.write( "+/- = - \n" ); document.write( "--------------- \n" ); document.write( "So it can be in the \n" ); document.write( "2nd or 4th qudrant \n" ); document.write( "----------------- \n" ); document.write( " \n" ); document.write( "I can say: \n" ); document.write( " \n" ); document.write( "---------------------------- \n" ); document.write( "I know that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------------- \n" ); document.write( "Hope I got it! \n" ); document.write( " |