document.write( "Question 1020364: The U.S. mint, which produces billions of coins annually, has a mean daily defect rate of 4 coins. Let X be the number of defective coins produced on a given day.\r
\n" ); document.write( "\n" ); document.write( "On a given day, what is the probability of 3 or fewer defective coins
\n" ); document.write( "On a given day, what is the probability of more than 3 defective coins?
\n" ); document.write( "On a given day, what is the probability of exactly 4 defective coins
\n" ); document.write( "what is the variance?\r
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Algebra.Com's Answer #636258 by robertb(5830)\"\" \"About 
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This is an example of a rare event, so the Poisson distribution is the most appropriate to use. \r
\n" ); document.write( "\n" ); document.write( "\"p%28x%29+=+%28mu%5Ex%2Fx%21%29%2Ae%5E%28-mu%29\"\r
\n" ); document.write( "\n" ); document.write( "The \"mu\" in this case is equal to 4.\r
\n" ); document.write( "\n" ); document.write( "==>The probability of 3 or fewer defective coins would be p(0) +p(1) + p(2) + p(3) = , to 5 decimal places.\r
\n" ); document.write( "\n" ); document.write( "==> The probability of more than 3 defective coins is 1 - 0.43347 = 0.56653.\r
\n" ); document.write( "\n" ); document.write( "The probability of exactly 4 defectives is \"p%284%29+=++%284%5E4%2F4%21%29%2Ae%5E%28-4%29=0.19537\", to 5 decimal places.\r
\n" ); document.write( "\n" ); document.write( "For the Poisson distribution, \"mu+=+sigma%5E2+=+4\".
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