document.write( "Question 1020294: A train leaves Orlando at 2:00 PM. A second train leaves the same city in the same direction at 5:00 PM. The second train travels 54 mph faster than the first. If the second train overtakes the first at 8:00 PM, what is the speed of each of the two trains? \n" ); document.write( "
Algebra.Com's Answer #636210 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A train leaves Orlando at 2:00 PM. \n" ); document.write( " A second train leaves the same city in the same direction at 5:00 PM. \n" ); document.write( " The second train travels 54 mph faster than the first. \n" ); document.write( " If the second train overtakes the first at 8:00 PM, what is the speed of each of the two trains? \n" ); document.write( ": \n" ); document.write( "When one train overtakes the other, they will have traveled the same distance \n" ); document.write( ": \n" ); document.write( "let s = the speed of the first train \n" ); document.write( "then \n" ); document.write( "(s+54) = the speed of the 2nd train \n" ); document.write( ": \n" ); document.write( "From the information given we know. \n" ); document.write( "6 hrs is the travel time of the 1st train \n" ); document.write( "3 hrs is the travel time of the 2nd train \n" ); document.write( ": \n" ); document.write( "Write a distance equation, dist = time * speed \n" ); document.write( "6s = 3(s+54) \n" ); document.write( "6s = 3s + 162 \n" ); document.write( "6s - 3s = 162 \n" ); document.write( "3s = 162 \n" ); document.write( "s = 162/3 \n" ); document.write( "s = 54 mph is the speed of the 1st train \n" ); document.write( "then \n" ); document.write( "54 + 54 = 108 mph is the speed of the 2nd train \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Makes sense; the 2nd train takes half as long as the first train because it goes twice as fast. \n" ); document.write( " |