document.write( "Question 1020249: The cost of petrol increased by 15% one week but fell back to the original price the next week.
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document.write( "By what percentage did the cost of petrol fall in the second week? \n" );
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Algebra.Com's Answer #636158 by Fombitz(32388) You can put this solution on YOUR website! Let's say the price starts at X. \n" ); document.write( " \n" ); document.write( "During the 15% increase, \n" ); document.write( " \n" ); document.write( "During the unknown decrease, \n" ); document.write( " \n" ); document.write( "Make that new price equal to the original price, X. \n" ); document.write( " \n" ); document.write( "You can divide X out of both sides. \n" ); document.write( "Now solve for Y. \n" ); document.write( " \n" ); document.write( "Subtract 1.15 from both sides \n" ); document.write( " \n" ); document.write( "Multiply both sides by 100 and divide both sides by 1.15. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "About a 13% decrease. \n" ); document.write( " \n" ); document.write( " |