document.write( "Question 1020249: The cost of petrol increased by 15% one week but fell back to the original price the next week.
\n" ); document.write( "By what percentage did the cost of petrol fall in the second week?
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Algebra.Com's Answer #636158 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Let's say the price starts at X.
\n" ); document.write( "\"P=X\"
\n" ); document.write( "During the 15% increase,
\n" ); document.write( "\"P=%281%2B15%2F100%29X=1.15X\"
\n" ); document.write( "During the unknown decrease,
\n" ); document.write( "\"P=%281%2BY%2F100%29%281.15X%29\" \"Y is the percentage decrease you're looking for\"
\n" ); document.write( "Make that new price equal to the original price, X.
\n" ); document.write( "\"%281%2BY%2F100%29%281.15%29X=X\"
\n" ); document.write( "You can divide X out of both sides.
\n" ); document.write( "Now solve for Y.
\n" ); document.write( "\"1.15%2B%281.15Y%29%2F100=1\"
\n" ); document.write( "Subtract 1.15 from both sides
\n" ); document.write( "\"%281.15%29Y%2F100=-0.15\"
\n" ); document.write( "Multiply both sides by 100 and divide both sides by 1.15.
\n" ); document.write( "\"Y=-15%2F1.15\"
\n" ); document.write( "\"Y=-13.04\"
\n" ); document.write( "About a 13% decrease.
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