document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87707>Question 87707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63607 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?<BR>\n" );
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document.write( "Let the width be x; the length will be \"x+1\".<BR>\n" );
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document.write( "Using Pythagoras:<BR>\n" );
document.write( "diagonal^2 = x^2 + (x+1)^2\r<BR>\n" );
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document.write( "16= 2x^2 + 2x +1\r<BR>\n" );
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document.write( "2x^2+2x-15 = 0\r<BR>\n" );
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document.write( "x = [-2+-sqrt(124)]/4<BR>\n" );
document.write( "Positive answer:<BR>\n" );
document.write( "x = [-2+sqrt(124)]/4\r<BR>\n" );
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document.write( "x = 2.28388... (width)<BR>\n" );
document.write( "x+1 = 3.28388... (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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