document.write( "Question 1020034: In 3 years, Jeff will be three times as old as his sister iya. A year ago, Jeff has 7 times as add as iya. How old are they now ? \n" ); document.write( "
Algebra.Com's Answer #635987 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "In 3 years, Jeff will be three \n" ); document.write( "times as old as his sister iya. \n" ); document.write( "J + 3 = 3(I + 3) \n" ); document.write( "J + 3 = 3I + 9 \n" ); document.write( "J = 3I + 6.......(1) \n" ); document.write( "A year ago, Jeff has 7 times \n" ); document.write( "as old as iya. \n" ); document.write( "J - 1 = 7(I - 1).....(2) \n" ); document.write( "Replace J in Eq(2) with \n" ); document.write( "3I + 6 from Eq(1) \n" ); document.write( "J - 1 = 7(I - 1) \n" ); document.write( "3I + 6 - 1 = 7(I - 1) \n" ); document.write( "3I + 5 = 7I - 7 \n" ); document.write( "Collect like terms \n" ); document.write( "3I - 7I = - 7 - 5 \n" ); document.write( "- 4I = - 12 \n" ); document.write( " I = -12/-4 \n" ); document.write( "I = 3 \n" ); document.write( "Jeff is 15 years old \n" ); document.write( "Iya is 3 years old \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |