document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1020018>Question 1020018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Estimate the approximate apparent solutions for 6x^2 + 13x – 5 = 0.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #635968 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=635968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Why approximate solutions when you can find their exact values?\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x%5E2+%2B+13x-5=%282x%2B5%29%283x-1%29=0 ALIGN=MIDDLE  ALT=\"6x%5E2+%2B+13x-5=%282x%2B5%29%283x-1%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "==> x = -5/2 (which is equal to -2.5) or x = 1/3 (approximately 0.3333). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );