document.write( "Question 1019847: I need some help with this problem:
\n" ); document.write( "Make a rough sketch of f if f'(2) = 0 and if f'(x) > 0 when x < 2 and if\"(x) < 0 when x > 2. \n" ); document.write( "
Algebra.Com's Answer #635961 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "In first and second derivatives, positive means \"upward to the right\",\r\n" );
document.write( "and negative means \"downward to the right\".\r\n" );
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document.write( "The first derivative f' determines slope of a tangent line, i.e., \r\n" );
document.write( "increasing or decreasing.\r\n" );
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document.write( "The second derivative f\" determines how the graph is curving, i.e., \r\n" );
document.write( "curving concave upward or curving concave downward.\r\n" );
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document.write( "f'(2) = 0 and if f'(x) > 0 when x < 2 and f\"(x) < 0 when x > 2.\r\n" );
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document.write( "f'(2) = 0 means that a tangent line drawn to the curve at the point\r\n" );
document.write( "where x=2 is horizontal.\r\n" );
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document.write( "f'(x) > 0 when x < 2 means that to the immediate left of the point\r\n" );
document.write( "where x=2, the curve is increasing, i.e., a tangent line drawn there\r\n" );
document.write( "slopes upward to the right. \r\n" );
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document.write( "f\"(x) < 0 when x > 2 means that the curvature to the immediate right\r\n" );
document.write( "of the point where x = 2 is downward. \r\n" );
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document.write( "The green lines are tangent lines.\r\n" );
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document.write( "Edwin
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