document.write( "Question 1019921: I was told to get a second opinion on this question -\r
\n" ); document.write( "\n" ); document.write( "Two gallons of milk contain 2% butterfat. How many quarts of milk should be drained and replaced by pure butterfat to produce a mixture of two gallons of milk containing 5% butterfat? (4 quarts in a gallon)
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Algebra.Com's Answer #635876 by LinnW(1048)\"\" \"About 
You can put this solution on YOUR website!
We have 2 gallons or 2*4 = 8 quarts of mixture
\n" ); document.write( "Let x be the number of quarts to replace with 100% fat to produce 5% mixture
\n" ); document.write( "(2%(8-x) + 100%(x) )/8 equals 5/100
\n" ); document.write( "That is 2% times the amount left after removing x quarts plus
\n" ); document.write( "100% times the same x quarts now being replaced
\n" ); document.write( "divided by 8, since we will continue to have 8 quarts.
\n" ); document.write( "This is set equal to 5/100 or 5%
\n" ); document.write( "\"%280.02%288-x%29+%2B+1%28x%29+%29%2F8+=+5%2F100\"
\n" ); document.write( "\"%280.16-0.02x+%2B+x+%29%2F8+=+5%2F100\"
\n" ); document.write( "\"%280.16%2B0.98x+%29%2F8+=+5%2F100\"
\n" ); document.write( "\"100%280.16%2B0.98x+%29+=+8%2A5\"
\n" ); document.write( "\"100%280.16%2B0.98x+%29+=+40\"
\n" ); document.write( "\"16%2B98x++=+40\"
\n" ); document.write( "add -16 to each side
\n" ); document.write( "\"98x++=+24\"
\n" ); document.write( "Divide each side by 98
\n" ); document.write( "x = 24/98
\n" ); document.write( "x = 0.2449 quarts
\n" ); document.write( "Double check
\n" ); document.write( "Substitute 0.2449 for x in \"%280.02%288-x%29+%2B+1%28x%29+%29%2F8\"
\n" ); document.write( "\"%280.02%288-0.2449%29+%2B+1%280.2449%29+%29%2F8\"
\n" ); document.write( "\"%280.02%287.7551%29+%2B+0.2449+%29%2F8\"
\n" ); document.write( "\"%280.400002+%29%2F8\"
\n" ); document.write( "0.05000025
\n" ); document.write( "5.000025% , so we have it
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