document.write( "Question 1019876: ) Find an equation of a line with the given properties and express the equation in slope-intercept form.\r
\n" ); document.write( "\n" ); document.write( "Passing through the point (2,7) and with slope ⅓\r
\n" ); document.write( "\n" ); document.write( "I may be heading the wrong direction with this one but I found a video that gave an example to use.\r
\n" ); document.write( "\n" ); document.write( "y=mx+b\r
\n" ); document.write( "\n" ); document.write( "and I have gotten this far with that ^\r
\n" ); document.write( "\n" ); document.write( "y=1/3x+ and then I've got nothing.
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Algebra.Com's Answer #635815 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Use the point-slope form of a line,
\n" ); document.write( "\"y-7=%281%2F3%29%28x-2%29\"
\n" ); document.write( "\"y-7=%281%2F3%29x-2%2F3\"
\n" ); document.write( "\"y=%281%2F3%29x-2%2F3%2B21%2F3\"
\n" ); document.write( "\"y=%281%2F3%29x%2B19%2F3\"
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\n" ); document.write( "You could also start with slope-intercept form and use the point to solve for b.
\n" ); document.write( "\"y=mx%2Bb\"
\n" ); document.write( "\"7=%281%2F3%292%2Bb\"
\n" ); document.write( "\"b=21%2F3-2%2F3\"
\n" ); document.write( "\"b=19%2F3\"
\n" ); document.write( "\"y=%281%2F3%29x%2B19%2F3\"
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