document.write( "Question 1019837: The total of two integers is forty three. Double the larger integer exceeds 3 times the smaller integer by sixteen. What are the integers? \n" ); document.write( "

Algebra.Com's Answer #635772 by LinnW(1048) $\"\"$ $\"About$

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Let I = the first integer
\n" ); document.write( "Let J = the second integer
\n" ); document.write( "I + J = 43
\n" ); document.write( "2J = 3I + 16
\n" ); document.write( "Rework I + J = 43 by adding -I to each side
\n" ); document.write( "J = 43 - I
\n" ); document.write( "Now substitute (43 - I) for J in 2J = 3I + 16
\n" ); document.write( "2(43 - I) = 3I + 16
\n" ); document.write( "86 - 2I = 3I + 16
\n" ); document.write( "add 2I to each side
\n" ); document.write( "86 = 5I + 16
\n" ); document.write( "add -16 to each side
\n" ); document.write( "70 = 5I
\n" ); document.write( "14 = I
\n" ); document.write( "Since J = 43 - I, substitute 14 for I
\n" ); document.write( "J = 43 - 14
\n" ); document.write( "J = 29
\n" ); document.write( "Checking our original equations
\n" ); document.write( "I + J = 43 , 14 + 29 = 43 so this checks out
\n" ); document.write( "2J = 3I + 16 , 2(29) = 3(14) + 16 , 58 = 42 + 16 , so this checks out \n" ); document.write( "

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