document.write( "Question 1019831: Width of a Rectangle is 4x. Which is 25% of it's length. ..find the area nd perimeter of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #635756 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Width = 4x \n" ); document.write( "Length = 16x (25% of 16 = 4) \n" ); document.write( "Area = Width x Length \n" ); document.write( "Area = 4x * 16x (* = times) \n" ); document.write( "Area = 64x^2 \n" ); document.write( "Perimeter = 2(Width) + 2(Length) \n" ); document.write( "Perimeter = 2(4x) + 2(16x) \n" ); document.write( "Perimeter = 8x + 32x \n" ); document.write( "Perimeter = 40x \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |