document.write( "Question 87672: Please help.I do not get this problem:
\n" ); document.write( " Graph f:x-> |x|+2 with domain D= { -2,-1,0,1,2} \n" ); document.write( "

Algebra.Com's Answer #63575 by Edwin McCravy(20086) $\"\"$ $\"About$

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document.write( "Please help.I do not get this problem:\r\n" );
document.write( "Graph f:x-> |x| + 2 with domain D = {-2,-1,0,1,2}\r\n" );
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document.write( "All you do is substitute each of those 5 numbers in the \r\n" );
document.write( "domain for x in the equation f(x) = |x| + 2:\r\n" );
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document.write( "f(-2) = |-2| + 2  = 2 + 2 = 4, so plot the point (-2,4)\r\n" );
document.write( "f(-1) = |-1| + 2  = 1 + 2 = 3, so plot the point (-1,3)\r\n" );
document.write( " f(0) =  |0| + 2  = 0 + 2 = 2, so plot the point  (0,2)\r\n" );
document.write( " f(1) =  |1| + 2  = 1 + 2 = 3, so plot the point  (1,3)\r\n" );
document.write( " f(2) =  |2| + 2  = 2 + 2 = 4, so plot the point  (2,4)\r\n" );
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document.write( "Here is all there is to the graph.\r\n" );
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document.write( "You don't connect the points since the domain just consists\r\n" );
document.write( "of 5 numbers, and so the graph just consists of those\r\n" );
document.write( "five points where the o's are, and no other points.\r\n" );
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document.write( "Edwin

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