document.write( "Question 1019564: A team plays 15 games a season. How many ways are there to
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document.write( "end up with 6 wins and 9 losses for the season. \n" );
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Algebra.Com's Answer #635745 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! A team plays 15 games a season. How many ways are there to \n" ); document.write( "end up with 6 wins and 9 losses for the season. \n" ); document.write( " \r\n" ); document.write( "There are two ways to work the problem:\r\n" ); document.write( "\r\n" ); document.write( "First way:\r\n" ); document.write( "\r\n" ); document.write( "There are 15 games, Choose 6 to win. (The rest are losses)\r\n" ); document.write( "\r\n" ); document.write( "Answer: 15C6 = 5005 ways.\r\n" ); document.write( "\r\n" ); document.write( "Second way:\r\n" ); document.write( "\r\n" ); document.write( "There are 15 games, Choose 9 to lose. (The rest are wins)\r\n" ); document.write( "\r\n" ); document.write( "Answer: 15C9 = 5005 ways.\r\n" ); document.write( "\r\n" ); document.write( "Notice that 15C6 = 15C9. It doesn't matter whether you choose\r\n" ); document.write( "the wins or the losses. The ones you don't choose for wins will\r\n" ); document.write( "automatically be losses, or vice-versa.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |