document.write( "Question 1019564: A team plays 15 games a season. How many ways are there to
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Algebra.Com's Answer #635745 by Edwin McCravy(20055)\"\" \"About 
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A team plays 15 games a season. How many ways are there to
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document.write( "There are two ways to work the problem:\r\n" );
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document.write( "First way:\r\n" );
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document.write( "There are 15 games, Choose 6 to win.  (The rest are losses)\r\n" );
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document.write( "Answer: 15C6 = 5005 ways.\r\n" );
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document.write( "Second way:\r\n" );
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document.write( "There are 15 games, Choose 9 to lose.  (The rest are wins)\r\n" );
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document.write( "Answer: 15C9 = 5005 ways.\r\n" );
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document.write( "Notice that 15C6 = 15C9.  It doesn't matter whether you choose\r\n" );
document.write( "the wins or the losses.  The ones you don't choose for wins will\r\n" );
document.write( "automatically be losses, or vice-versa.\r\n" );
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document.write( "Edwin
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