document.write( "Question 1019792: Need help with this Calculus problem please.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Find an equation for the line tangent to the curve when x has the first value.\r
\n" ); document.write( "\n" ); document.write( "y=3√x
\n" ); document.write( "x=4
\n" ); document.write( "x=9
\n" ); document.write( "

Algebra.Com's Answer #635727 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
If \"y+=+3sqrt%28x%29\", then the derivative is the function \"dy%2Fdx=3%2F%282sqrt%28x%29%29\"
\n" ); document.write( "==> when x = 4, \"dy%2Fdx+=+3%2F4\", which is the slope of the line tangent at the point (4,6) of the curve.\r
\n" ); document.write( "\n" ); document.write( "==> \"y+-+6+=+%283%2F4%29%28x-4%29\"
\n" ); document.write( "<==> 4y - 24 = 3x - 12
\n" ); document.write( "<==> 3x - 4y +12 = 0 is the tangent line.\r
\n" ); document.write( "\n" ); document.write( "For x = 9, the procedure is the same.
\n" ); document.write( "
\n" );