document.write( "Question 1019753: Solve for x, check for any extraneous solutions.
\n" ); document.write( "sqrt(2x+1) -8= -5\r
\n" ); document.write( "\n" ); document.write( "I got x=-5 and x=4. I don't know if this correct. Please help me clarify this. Thanks!
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Algebra.Com's Answer #635692 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Solve for x, check for any extraneous solutions.
\n" ); document.write( "sqrt(2x+1) -8= -5\r
\n" ); document.write( "\n" ); document.write( "I got x=-5 and x=4.
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document.write( "You apparently know how to solve equations with \r\n" );
document.write( "square roots. You only need to learn how to check \r\n" );
document.write( "your answers. You must always check answers in \r\n" );
document.write( "equations containing square roots, for they often\r\n" );
document.write( "give bogus solutions.\r\n" );
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document.write( "\"sqrt%282x%2B1%29+-8=+-5\"\r\n" );
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document.write( "Let's check your first answer x=-5\r\n" );
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document.write( "\"sqrt%282%28-5%29%2B1%29+-8=+-5\"\r\n" );
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document.write( "\"sqrt%28-10%2B1%29+-8=+-5\"\r\n" );
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document.write( "\"sqrt%28-9%29+-8=+-5\"\r\n" );
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document.write( "That has a neative number under a square root,\r\n" );
document.write( "so it cannot be a real number. So -5 is an\r\n" );
document.write( "extraneous solution.  So we discard it.\r\n" );
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document.write( "\"sqrt%282x%2B1%29+-8=+-5\"\r\n" );
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document.write( "Let's check your second answer x=4\r\n" );
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document.write( "\"sqrt%282%284%29%2B1%29+-8=+-5\"\r\n" );
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document.write( "\"sqrt%288%2B1%29+-8=+-5\"\r\n" );
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document.write( "\"sqrt%289%29+-8=+-5\"\r\n" );
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document.write( "\"3+-8=+-5\"\r\n" );
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document.write( "\"-5=+-5\"\r\n" );
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document.write( "That one checks.  So x = 4 is the only\r\n" );
document.write( "solution.\r\n" );
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document.write( "Edwin
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