document.write( "Question 87643: Please help me to solve the following problems:\r
\n" ); document.write( "\n" ); document.write( "76) 3/2y-3/2y+4\r
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\n" ); document.write( "\n" ); document.write( "82) 4/3n+2/n+1+2/n^2+n\r
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Algebra.Com's Answer #63565 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
solve the following problems:
\n" ); document.write( "76) 3/2y-3/2y+4
\n" ); document.write( "3/(2y) - 3/(2y+4)
\n" ); document.write( "You need a lcd (least common denominator):
\n" ); document.write( "That would be 2y(2y+4)
\n" ); document.write( "Rewrite each fraction with that lcd as its denominator:
\n" ); document.write( "[3(2y+4)]/lcd - [3(2y)]/lcd
\n" ); document.write( "Combine the numerators to get:
\n" ); document.write( "= [12y+12]/lcd
\n" ); document.write( "Simplify:
\n" ); document.write( "= 12(y+1)/(2y)(2y+4)
\n" ); document.write( "= 12(y+1)/[4y(y+2)]
\n" ); document.write( "= 3(y+1)/y(y+2)
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\n" ); document.write( "\n" ); document.write( "82) 4/(3n) + 2/(n+1) + 2/(n^2+n)
\n" ); document.write( "lcd = 3n(n+1)
\n" ); document.write( "Rewrite:
\n" ); document.write( "= 4(n+1)/lcd + 2(3n)/lcd + 2(3)/lcd
\n" ); document.write( "= [4n+4+6n+6]/lcd
\n" ); document.write( "= [10(n+1)]/[3n(n+1)]
\n" ); document.write( "= 10/3n
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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