document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1019688>Question 1019688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two number differ by 2 and are such that three times one number added is five times the other number gives 46 find the two numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #635638 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=635638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Two number differ by 2<BR>\n" );
document.write( "Make one number = 'x'<BR>\n" );
document.write( "Other number = 'x + 2'<BR>\n" );
document.write( " Three times one number added is <BR>\n" );
document.write( "five times the other number gives 46 <BR>\n" );
document.write( "3(x) + 5(x + 2) = 46<BR>\n" );
document.write( "3x + 5x + 10 = 46<BR>\n" );
document.write( "3x + 5x = 46 - 10<BR>\n" );
document.write( "8x = 36<BR>\n" );
document.write( "x = 4.5<BR>\n" );
document.write( "One number = 4.5<BR>\n" );
document.write( "Other number = 6.5<BR>\n" );
document.write( "3(4.5) + 5(4.5 + 2) = 46<BR>\n" );
document.write( "3(4.5) + 5(6.5) = 46<BR>\n" );
document.write( "13.5 + 32.5 = 46<BR>\n" );
document.write( "46 = 46<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );