document.write( "Question 1019621: 1. Solve sqrt2x + x = 4 for x.
\n" ); document.write( "Answers: A. x = 2 B. The two solutions are for complex numbers.
\n" ); document.write( "C. x = 2 or x = 8 ( I picked C and it was wrong) D. x = 4 or x = -4\r
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Algebra.Com's Answer #635577 by josgarithmetic(39616)\"\" \"About 
You can put this solution on YOUR website!
Your text is not well written so one could guess you have sqrt(2x)+x=4, which would best appear \"sqrt%282x%29%2Bx=4\".\r
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\n" ); document.write( "\n" ); document.write( "Isolate the radical.
\n" ); document.write( "\"sqrt%282x%29=4-x\"\r
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\n" ); document.write( "\n" ); document.write( "Square the equated members.
\n" ); document.write( "\"2x=%284-x%29%5E2\"
\n" ); document.write( "\"2x=16-8x%2Bx%5E2\"
\n" ); document.write( "Simplify and solve.
\n" ); document.write( "\"x%5E2-8x-2x%2B16=0\"
\n" ); document.write( "\"x%5E2-10x%2B16=0\"
\n" ); document.write( "\"%28x-2%29%28x-8%29=0\"
\n" ); document.write( "and if you check you find both x=2 and x=8 will work.
\n" ); document.write( "x=2 OR x=8.
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