document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1019602>Question 1019602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father was 24 years old when his son was born. Now he is three times as old as his son. Find his son's age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #635555 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=635555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the son's age x. Now the father is 24 plus the age of his son:<BR>\n" );
document.write( "24+x = 3x subtract x on both sides<BR>\n" );
document.write( "24 = 2x flip the equation around, it looks better:<BR>\n" );
document.write( "2x = 24 now divide both sides by 2<BR>\n" );
document.write( "x = 12 is the son's age. And the father is:<BR>\n" );
document.write( "12+24 = 36 <BR>\n" );
document.write( "And the son's age times 3:<BR>\n" );
document.write( "12*3 = 36 we have the correct answer </SPAN>\n" );
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