document.write( "Question 1019566: A biker decided to cover the distance of 120 km at a certain speed. However, he actually went 6 km/h slower so he arrived at his destination 1 hour later than he wanted to. What was the actual speed of the biker? What is the equation? \n" ); document.write( "
Algebra.Com's Answer #635535 by ankor@dixie-net.com(22740)\"\" \"About 
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A biker decided to cover the distance of 120 km at a certain speed.
\n" ); document.write( " However, he actually went 6 km/h slower so he arrived at his destination 1 hour later than he wanted to.
\n" ); document.write( " What was the actual speed of the biker?
\n" ); document.write( " :
\n" ); document.write( "let s = actual speed of the biker
\n" ); document.write( "He went 6 km/hr slower, therefore
\n" ); document.write( "(s+6) = speed he intended to travel
\n" ); document.write( ":
\n" ); document.write( "Write a time equation time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Actual time - intended time = 1 hrs
\n" ); document.write( "\"120%2Fs\" - \"120%2F%28%28s%2B6%29%29\" = 1
\n" ); document.write( "multiply equation by s(s+6)
\n" ); document.write( "s(s+6)*\"120%2Fs\" - s(s+6)\"120%2F%28%28s%2B6%29%29\" = 1s(s+6)
\n" ); document.write( "cancel the denominators
\n" ); document.write( "120(s+6) - 120s = s^2 + 6s
\n" ); document.write( "120s + 720 - 120s = s^2 + 6s
\n" ); document.write( "Form a quadratic equation on the right
\n" ); document.write( "0 = s^2 + 6s - 720
\n" ); document.write( "You can use the quadratic formula; a=1; b=6; c=-720, but this will factor to
\n" ); document.write( "(s+30)(s-24) = 0
\n" ); document.write( "the positive solution;
\n" ); document.write( "s = 24 km/hr actual speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this solution; find the actual time at each speed
\n" ); document.write( "120/24 = 5 hrs
\n" ); document.write( "120/30 = 4 hrs
\n" ); document.write( "---------------
\n" ); document.write( "differs: 1 hr
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