document.write( "Question 1019566: A biker decided to cover the distance of 120 km at a certain speed. However, he actually went 6 km/h slower so he arrived at his destination 1 hour later than he wanted to. What was the actual speed of the biker? What is the equation? \n" ); document.write( "
Algebra.Com's Answer #635535 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A biker decided to cover the distance of 120 km at a certain speed. \n" ); document.write( " However, he actually went 6 km/h slower so he arrived at his destination 1 hour later than he wanted to. \n" ); document.write( " What was the actual speed of the biker? \n" ); document.write( " : \n" ); document.write( "let s = actual speed of the biker \n" ); document.write( "He went 6 km/hr slower, therefore \n" ); document.write( "(s+6) = speed he intended to travel \n" ); document.write( ": \n" ); document.write( "Write a time equation time = dist/speed \n" ); document.write( ": \n" ); document.write( "Actual time - intended time = 1 hrs \n" ); document.write( " \n" ); document.write( "multiply equation by s(s+6) \n" ); document.write( "s(s+6)* \n" ); document.write( "cancel the denominators \n" ); document.write( "120(s+6) - 120s = s^2 + 6s \n" ); document.write( "120s + 720 - 120s = s^2 + 6s \n" ); document.write( "Form a quadratic equation on the right \n" ); document.write( "0 = s^2 + 6s - 720 \n" ); document.write( "You can use the quadratic formula; a=1; b=6; c=-720, but this will factor to \n" ); document.write( "(s+30)(s-24) = 0 \n" ); document.write( "the positive solution; \n" ); document.write( "s = 24 km/hr actual speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this solution; find the actual time at each speed \n" ); document.write( "120/24 = 5 hrs \n" ); document.write( "120/30 = 4 hrs \n" ); document.write( "--------------- \n" ); document.write( "differs: 1 hr \n" ); document.write( " |