document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87647>Question 87647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ladder 10 ft long leans against a wall. The bottom of the ladder is 6 ft from the wall. How much would the lower end of the ladder have to be pulled away so that the top end would be pulled down by 3 ft?\r<BR>\n" );
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document.write( "thnx.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63553 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> right angled triangle --> use Pythagoras. Find the height of the ladder in the first instance then subtract 3 from that answer and recalculate the floor distance using that new height remembering that the hypotenuse is fixed at 10.\r<BR>\n" );
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document.write( "The first part is a really quick calculation because you have the classic 3,4,5 Pythagorean sides scaled up--> 6,8,10\r<BR>\n" );
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document.write( "cheers<BR>\n" );
document.write( "Jon </SPAN>\n" );
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