document.write( "Question 87644: Please help me solve the following equations:\r
\n" ); document.write( "\n" ); document.write( "50) a+4/2 = a+4/a\r
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\n" ); document.write( "\n" ); document.write( "64) 4w-1/3w+6 - w-1/3 = w-1/w+2\r
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Algebra.Com's Answer #63551 by madhujiithcharu@yahoo.co.in(28)\"\" \"About 
You can put this solution on YOUR website!
a+4/2 = a+4/a => 1/2 = 1/a => a = 2\r
\n" ); document.write( "\n" ); document.write( "64)4w-1/3w+6 - w-1/3 = w-1/w+2
\n" ); document.write( " 4w-1/3(w+2)- w-1/3 = w-1/w+2
\n" ); document.write( " 4w-1-(w+2)(w-1)/3(w+2) = w-1/w+2
\n" ); document.write( " 4w-1-w^2-w+2/3 = w-1
\n" ); document.write( " -w^2+3w+1 = 3w-3
\n" ); document.write( " -w^2 = -4
\n" ); document.write( " w^2 = 4
\n" ); document.write( " w = \/4 => w = 2, w=-2
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