document.write( "Question 12495: please help me solve this equation: 3x-2=x +8 \n" ); document.write( "
Algebra.Com's Answer #6355 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
The idea here is to get the variable, x in this case, to one side of the = and the numbers on the other side using the rules of algebra.\r
\n" ); document.write( "\n" ); document.write( "\"3x+-+2+=+x+%2B+8\" Subtract x from both sides.\r
\n" ); document.write( "\n" ); document.write( "\"3x+-+2+-+x+=+x+%2B+8+-+x\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+-+2+=+8\" Now add 2 to both sides.\r
\n" ); document.write( "\n" ); document.write( "\"2x+-+2+%2B+2+=+8+%2B+2\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+=+10\" Finally, divide both sides by 2 because you want x = ??? not 2x = ???\r
\n" ); document.write( "\n" ); document.write( "\"2x%2F2+=+10%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+5\"\r
\n" ); document.write( "\n" ); document.write( "To check the solution, you substitute 5 in place of x (all of them) in the original equation and, if the rwo sides are equal, then the solutionis correct. If not, then it's back to the drawing board.\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"3x+-+2+=+x+%2B+8\"
\n" ); document.write( "\"3%285%29+-+2+=+5+%2B+8\"
\n" ); document.write( "\"15+-+2+=+13\"
\n" ); document.write( "\"13+=+13\" The solution is correct!\r
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