document.write( "Question 1019528: Ten men working for 6 days of 10 hours each, finish 5/21 of a piece of work . How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 day? \n" ); document.write( "
Algebra.Com's Answer #635486 by robertb(5830)\"\" \"About 
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The total number of man hours (for the first 6 days) required to finish 5/21 of the work is 10*6*10 = 600 man-hours. Hence each man contributes \"%285%2F21%29%2F600+=+1%2F2520\" for the entire job.
\n" ); document.write( "Now 16/21 of the job still had to be done, and the job had to be done at the same rate and at the same number of hours each day.
\n" ); document.write( "Note that 16/21 of the job had to be completed in 2 more days. (2 additional days after initial 6 days.)
\n" ); document.write( "Let m = number of men required to complete the job in two more days\r
\n" ); document.write( "\n" ); document.write( "Hence...\r
\n" ); document.write( "\n" ); document.write( "\"%281%2F2520%29%2Am%2A2%2A10+=+16%2F21\"
\n" ); document.write( "==> \"m%2F126+=+16%2F21\"
\n" ); document.write( "==> m = 96.
\n" ); document.write( "Therefore it will take 96 men to finish the job in two more days at the same rate and same number of hours each day.\r
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