document.write( "Question 87630: Solve by completing the square\r
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document.write( "x^2+4x-3=0 \n" );
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Algebra.Com's Answer #63543 by madhujiithcharu@yahoo.co.in(28)![]() ![]() ![]() You can put this solution on YOUR website! x^2 + 4x - 3 = 0 \n" ); document.write( " x = -4 + or - \/ 16-4(1)(-3) / 2 \n" ); document.write( " = -4 + or - \/28 / 2 \n" ); document.write( " = -4 + or - 2\/7 /2 \n" ); document.write( " = -2 + or - \/7\r \n" ); document.write( "\n" ); document.write( "therefore x = -2 + \/7 , x = -2 - \/7 \n" ); document.write( " |