document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1019276>Question 1019276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For a normally distributed variable with a mean of 10 and standard deviation of 5, what is the proportion of the data with negative values? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #635424 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=635424\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the data has a mean of 10 and a standard deviation of 5, negative values would be present when they are more than two s.d. away...two s.d. covers 95% of the data...that means 2.5% of the data is negative...<BR>\n" );
document.write( "Or if you wanted negative to positive, that would be 2.5 / 97.5 = 1/39. </SPAN>\n" );
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