document.write( "Question 1019468: when x=3 what is the value of f(x)=2(.75)^x.\r
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document.write( "I did it and i got 0.84 am i right? \n" );
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Algebra.Com's Answer #635406 by fractalier(6550) You can put this solution on YOUR website! We have f(x) = 2(.75)^x and we need \n" ); document.write( "f(3) = 2(.75)^3 = 2(.422) = .844 \n" ); document.write( "We have a winner! \n" ); document.write( " |