document.write( "Question 1019468: when x=3 what is the value of f(x)=2(.75)^x.\r
\n" ); document.write( "\n" ); document.write( "I did it and i got 0.84 am i right?
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Algebra.Com's Answer #635406 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
We have f(x) = 2(.75)^x and we need
\n" ); document.write( "f(3) = 2(.75)^3 = 2(.422) = .844
\n" ); document.write( "We have a winner!
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