document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1019332>Question 1019332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A recipe for chocolate requires a 5:4 ratio of cocoa beans to milk. How many gallons of milk must be purchased if you are using 80 pounds of cocoa beans? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #635404 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=635404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the ratio of cocoa beans to milk is 5 to 4.\r<BR>\n" );
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document.write( "that's presumably 5 pounds of cocoa beans to 4 gallons of milk.\r<BR>\n" );
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document.write( "assuming that's true, then your ratio is c/m = 5/4.\r<BR>\n" );
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document.write( "c = number of pounds of cocoa beans.<BR>\n" );
document.write( "m = gallons of milk.\r<BR>\n" );
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document.write( "if you have 80 pounds of cocoa beans, then c/m = 4/5 becomes:\r<BR>\n" );
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document.write( "80/m = 4/5\r<BR>\n" );
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document.write( "cross multiply to get 5m = 4*80.\r<BR>\n" );
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document.write( "this becomes 5m = 320.\r<BR>\n" );
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document.write( "divide both sides of this equation by 5 to get m = 64.\r<BR>\n" );
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document.write( "80 pounds of cocoa beans requires 64 gallons of milk.\r<BR>\n" );
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document.write( "the ratio of 80 / 64 can be simplified to 5/4 by dividing both numerator and denominator by 16.\r<BR>\n" );
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document.write( "you get (80/16) / (64/16) = 5/4.\r<BR>\n" );
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