document.write( "Question 1019368: You invested a total of $12,000 at 4 1/ 2 % and 5% simple interest. During one year, the two accounts earned $580. How much did you invest in each account? \n" ); document.write( "
Algebra.Com's Answer #635399 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call the amount invested at 4.5%, x. \n" ); document.write( "Then the amount invested at 5% must be 12000-x. \n" ); document.write( "The setup looks like this: \n" ); document.write( ".045x + .05(12000-x) = 580 \n" ); document.write( "Now work it out... \n" ); document.write( ".045x + 600 - .05x = 580 \n" ); document.write( "-.005x = -20 \n" ); document.write( "x = $4000 invested at 4.5% so that \n" ); document.write( "12000-x = $8000 at 5% \n" ); document.write( " |