document.write( "Question 87617: Please i need help with this problem:\r
\n" ); document.write( "\n" ); document.write( " The water level of a swimming pool, 75 feet by 42 feet, is to be raised 4 inches. The number of gallons of water needed for this purpose is....
\n" ); document.write( "(1 cubic foot equals 7 1/2 gallons)
\n" ); document.write( "

Algebra.Com's Answer #63538 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Volume of water needed = 75 feet by 42 feet by 4 inches.
\n" ); document.write( "V= 75*42*1/3=1050 cubic feet\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Convert to gallons by multiplying by 7.5 gallons per cubic foot
\n" ); document.write( "V= 1050*7.5 = 7875 gallons.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 Retired from SCC
\n" ); document.write( "
\n" );